(x+1)^2=(2-x)^2 помогите

(x+1)² - (2-x)² =0(x+1-(2-x))(x+1+2-x)=0(x+1-2+x)*3 =03(2x-1)=02x-1=02x=1x=0.5

(X+1)^2 = (2-x)^2 x^2 + 2x + 1 = 4 - 4x + x^2 x^2 - x^2 + 2x + 4x +1 - 4 = 0 6x - 3 = 0 6x = 3 X = 2