упростите выражение sin2п/3cosп/3+cosп/3sinп/3

sin(2π/3)cos(π/3) + cos(π/3)sin(π/3) = 2sin(π/3)cos(π/3)cos(π/3) + + sin(π/3)cos(π/3) = sin(π/3)cos(π/3) * [2cos(π/3) + 1] = = (√3/2)*(1/2)* [ 2*(1/2) + 1] = (√3/4) * 2 = √3/2