а) 12х(х-3)=(6-х)(х+2)
б) (х+4)(х+1)=х-(х-2)(2-х)

a) 12(x-3)=(6-x)(x+2)12x - 36 = 6x - x^2 - 2x  +12x^2 + 8x - 48 = 0D/4 = 16+48  =64x1 = -4+8 = 4x2 = -4 - 8 = -12б)(x+4)(x+1) = x - (x-2)(2-x)(x+4)(x+1) = 1 + (x-2)^2x^2  + 4x  +x  +4 = 1 + x^2 - 4x + 45x + 4 = 5 - 4x9x = -1x= -1/9