12а-4а (в квадрате)+10-2а+а ( в квадрате) Решите пжлст - №10198935

12а-4а (в квадрате)+10-2а+а ( в квадрате) Решите пжлст
- Предмет:
  Алгебра
- Автор:
  blankenship
- 6 лет назад

Ответы 1

12a-4a²+10-2a+a²=10a-3a²+10=0d=10²-4(-3)10=100+120=220a=(-10+-14.8)/2*(-3)a1=4.8/-6= -0.8a2=-24.8/-6=4.13
- Автор:
  buttercupi42r
- 6 лет назад
- 0
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