найти log(24) 72 если log(6)2=m

log₂₄(72) =  log₆ 72 /log₆ 24 =  log₆ (36*2) / log₆ (2*2*6) == [log₆ (6²) + log₆ 2] / [ log₆ 2 + log₆ 2 + log₆ 6]Если log₆ 2 = m ,  то [2m + m] / [m + m + 1] =  3m / (2m+1)