Решите уравнение: cos^2 x(x+pi/3)=1

cos²(x + π/3) = 11) cos(x + π/3) = - 1 x + π/3 = π + 2πk, k ∈zx = - π/3 + π + 2πk, k ∈zx = 2π/3 + 2πk, k ∈z2) cos(x + π/3) = 1 x + π/3 = 2πn, n∈Z x= - π/3 + 2πn, n∈Z

sin²(x + π/3) = 11) sin(x + π/3)  = - 1 x + π/3 = - π/2 + 2πk, k ∈zx = - π/3 - π/2 + 2πk, k ∈zx = - 5π/6 + 2πk, k ∈z2) sin(x + π/3)  = 1 x + π/3  = π/2 + 2πn, n∈Z x=  - π/3  + π/2 + 2πn, n∈Z x=  π/6 + 2πn, n∈Z

cos²(x+π/3)=1[1+cos(2x+2π/3)]/2=11+cos(2x+2π/3)=2cos(2x+2π/3)=12x+2π/3=2πn2x=-2π/3+2πnx=-π/3+πn