Решите уравнение: (2х-7)^2(x-7)=(2x-7)(x-7)^2

(2x - 7)^2 *(x - 7) = (2x - 7) (x - 7)^2(2x - 7)^2 *(x - 7) -  (2x - 7) (x - 7)^2 = 0 (x - 7) (2x - 7) (2x - 7 - (x - 7)) = 0 (x - 7) (2x - 7) ( 2x - 7 - x + 7) = 0 x (x - 7) (2x - 7) = 0x = 0 x = 7 x = 3,5