x^2+y^2=41
xy=20
решите систему кв.уравнений,пожалуйста)

x*2 + y*2 +2xy-2xy=41(x+y)*2 = 41+2xy(x+y)*2 = 41+40(x+y)*2 = 81x+y = 9x=9-y(9-y)y=20y*2 - 9y + 20 = 0(y - 9/2)*2 = -20 + 81/4(y-9/2)*2 = 1/4y-9/2 = 1/2y = 1/2 + 9/2y = 5x = 9-5 =4