Решите пожалуйста!
4(cos^2 (x/3) + sin (x/3))=1

4-4sin²(x/3)+sin(x/3)-1=04sin²(x/3)-sin(x/3)-3=0sin(x/3)=a4a²-a-3=0D=1+48=49a1=(1-7)/8=-3/4⇒sin(x/3)=-3/4⇒x/3=(-1)^n+1*arcsin3/4+πn⇒x=(-1)^n+1*3arcsin3/4+3πna2=(1+7)/8=1⇒sin(x/3)=1⇒x/3=π/2+πn⇒x=3π/2+3πn

4a²-a-3=0a₁=(1-7)/8=-3/4sin(x/3)=-3/4x/3=(-1)^n+arcsin3/4+πnx=(-1)^n+3arcsin3/4+3πna₂=(1+7)/8=1sin(x/3)=1x/3=π/2+πnx=3π/2+3πn