Решить систему [tex] \left \{ {{log_3x + log_9y = 3 } \atop {log_(1/5)x + log_3y = 3}} ight. [/tex]
3,9, 1/5 - основание логарифма

log(3)x+log(9)y=3log(9)y=3-log(3)xlog(3)y/2=3-log(3)xlog(3)y=6-2log(3)xПодставим во 2log(1/5)x+log(3)y=3log(1/5)x+6-2log(3)x=3-log(3)x/log(3)5 -2log(3)x+3=0-log(3)x-2log(5)3*log(3)x+3log(3)5=0-log(3)x *(1+2log(3)5)=-3log(3)5log(3)x=3log(3)5/(1+2log(3)5)  log(3)x=  log(3)125/log(3)75=log(75)125x=3^log(75)125