Решите уравнения x2 +6=5x
2-3(2x+2)=5-4x
-2(5-3x)=7x+3
1-2(5-2x)=-x-3

х^2+6=5х. х^2-5х+6=0. Д=25-4×1×6=1. х1=(5-1)/2=2. х2=(5+1)/2=3

2-3(2х+2)=5-4х2-6х-6=5-4х-6х+4х=5-2+6-2х=9х=-9÷2х=-4.5-2(5-3х)=7х+3-10+6х=7х+36х-7х=3+10-х=13х=-131-2(5-2х)=-х-31-10+4х=-х-34х-9=-х-34х+х=-3+95х=6х=6÷5х=1.2