Помогите срочно!! Очень надо!! Пожалуйста!!!!!!!!!!!!!!!!!!!!!!!!!!!!

1) y = 5 - 3lnx,   x₀ = 4y` = - 3/xy`(4) = - 3/42) y = x³/2 - ln(2x),      x₀ = 2y` = (3x²)/2 - 2/(2x) = (3x²)/2 - 1/xy`(2) = (3*4)/2 - 1/2 = 11/2 =  5,53)  f(x) = 6cos(π/3 - 3x) = 6cos(3x - π/3),   x₀ = π/6f1(x) = - 18sin(3x - π/3)f`(π/6) = - 18sin(3*π/6 - π/3) = - 18sin(π/2 - π/3) = - 18sin(π/6) = - 18*(1/2) = - 9