Составьте уравнение касательной к графику функции y = x^3 - 2x^2 - 3x + 5 в точке с абсциссой x = -2

Составьте уравнение касательной к графику функции y = x^3 - 2x^2 - 3x + 5 в точке с абсциссой x = -2
- Предмет:
  Алгебра
- Автор:
  higginslogan
- 5 лет назад

Ответы 1

f(x) = x³ - 2x² - 3x + 5 , x₀ = -2f(x₀) = f(-2) = (-2)³ - 2·(-2)² - 3·(-2) + 5 = -8 - 8 + 6 + 5 = - 5f '(x) = 3x² - 4x - 3f '(x₀) = f '(-2) = 3·(-2)² - 4·(-2) - 3 = 12 + 8 - 3 = 17y = f(x₀) + f '(x₀)(x - x₀)y = -5 + 17(x + 2) = -5 + 17x + 34 = 29 + 17x
- Автор:
  kibblesv48u
- 5 лет назад
- 0
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Составьте уравнение касательной к графику функции y = x^3 - 2x^2 - 3x + 5 в точке с абсциссой x = -2

Ответы 1

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