• Решите систему уравнений:
    а) [tex] \left \{ {{ x^{2} +4xy+4y ^{2}=7x+14y } \atop {2x+5y=15}} ight. [/tex]
    б)[tex]. \left \{ {{9y^{2}-6xy-5x+ x^{2}+15y=0 } \atop {3x-4y=20}} ight. [/tex]

Ответы 1

  •  \left \{ {{x^2+4xy+4y^2=7x+14y} \atop {2x+5y=15}} ight.  \left \{ {{(x+2y)^2=7(x+2y)} \atop {2x+5y=15}} ight.  \left \{ {{x+2y=7} \atop {2x+5y=15}} ight.  \left \{ {{x=7-2y} \atop {2(7-2y)+5y=15}} ight. \left \{ {{x=7-2y} \atop {14-4y+5y=15}} ight. \left \{ {{x=7-2y} \atop {14+y=15}} ight. \left \{ {{x=7-2y} \atop {y=15-14}} ight.  \left \{ {{x=7-2*1} \atop {y=1}} ight.  \left \{ {{y=5} \atop {y=1}} ight.  \left \{ {{9y^2-6xy-5x+x^2+15y=0} \atop {3x-4y=20}} ight.  \left \{ {{9y^2-6xy+x^2=5x-15y} \atop {3x-4y=20}} ight. \left \{ {{(3y-x)^2=-5(3y-x)} \atop {3x-4y=20}} ight.  \left \{ {{3y-x=-5} \atop {3x-4y=20}} ight. \left \{ {{-x=-5-3y} \atop {3x-4y=20}} ight.   \left \{ {{x=5+3y} \atop {3x-4y=20}} ight.    \left \{ {{x=5+3y} \atop {3(5+3y)-4y=20}} ight.    \left \{ {{x=5+3y} \atop {15+9y-4y=20}} ight.     \left \{ {{x=5+3y} \atop {5y=20-15}} ight.   \left \{ {{x=5+3y} \atop {5y=5}} ight.   \left \{ {{x=5+3*1} \atop {y=1}} ight.    \left \{ {{x=8} \atop {y=1}} ight.
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