1-sinx=sinx 2cos2x=2. 5-5sinx=cos2x

1) 1 - sin x = Sin x2Sin x = 1Sin x = 1/2x = (-1)^n arcSin 1/2 + nπ, n∈Zx = (-1)^n π/6 + nπ,n∈Z2) 2 Cos x = 2Cos x = 1x = 2πk , k∈Z3) 5 - 5 Sin x = Cos2x    5 - 5Sin x = 1 - 2Sin² x    2 Sin² x -5Sin x +4 = 0Sin x = t2t² - 5t +4 = 0D = 1t1= 3/2t2 = 1a) Sin x = 3/2нет решенийб) Sin x = 1     x = π/2 + 2πk , k∈Z