tg3x>√3
3x=t
tgt>√3
t1=pi/3+2pik . k=z
t2=-2pi/3+2pik . k=z
t1=(pi/3+2pik;pi/2+2pik) . k=z
t1=(-pi/2+2pik;-2pi/3+2pik) . k=z
Заменим t на x:
t=3x
1)pi/3=3x
x=pi/9
2)-2pi/3=3x
x=-2pi/9
Запишим ответ в x:
x1=(pi/9+2pik;pi/2+2pik) . k=z
x2=(-pi/2+2pik;-2pi/9+2pik) . k=z
Автор:
big macdl3aДобавить свой ответ
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