Как решать?Log4 (x+2)*Logx 2 =1 - №1215335

Как решать?
Log4 (x+2)*Logx 2 =1
- Предмет:
  Алгебра
- Автор:
  felix80
- 6 лет назад

Ответы 1

$x+2>0; x>-2\\ x>0, xeq1\\ log_4(x+2)\frac{log_42}{log_4x}=1\\ \frac{log_4(x+2)}{2log_4x}=1\\ log_4(x+2) = log_4x^2\\ x^2 - x - 2 = 0\\ x = 2, x=-1$

x = -1 - не подходит

х = 2
- Автор:
  hoochhjoc
- 6 лет назад
- 0
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