2sin(x/2-pi/6)=-1 помогите пожалуйста

Решение2sin(x/2 - π/6) = - 1sin(x/2 - π/6) = - 1/2x/2 - π/6 = (-1)^(n)*arcsin(-1/2) + πn. n∈Zx/2 - π/6 = (-1)^(n+1)*arcsin(1/2) + πn. n∈Zx/2 - π/6 = (-1)^(n+1)*(π/6) + πn. n∈Zx/2  = (-1)^(n+1)*(π/6) + π/6 + πn. n∈Zx  = (-1)^(n+1)*(π/3) + π/3 + 2πn. n∈Z