1)y`=3x²+2x-8=0D=4+96=100x1=(-2-10)/6=-2∈[-3;0]x2=(-2+10)/6=4/3∉[-3;0]y(-3)=-27+9+24-8=-2y(-2)=-8+4+16-8=4наибy(0)=0+0-0-8=-8наим2)y`=3x²-8x-3=0D=64+36=100x1=(8-10)/6=-1/3∉[0;6]x2=(8+10)/6=3∈[0;6]y(0)=0-0-0-11=-11наибy(3)=27-36-9-11=-29y(6)=64-144-18-11=-109наим3)y`=3x²+8x-3=0D=64+36=100x1=(-8-10)/6=-3∈[-4;0]x2=(-8+10)/6=1/3∉[-4;0]y(-4)=-64+64+12-7=5y(-3)=-27+36+9-7=11наибy(0)=0+0-0-7=-7наим