рншить уравнение
sin3x + cos3x=(корень из 2)sin x

sin3x+sin(π/2-3x)=√2sinx2sinπ/4cos(3x-π/4)=√2sinx√2cos(3x-π/4)-√2cos(π/2-x)=0√2(cos(3x-π/4)-cos(π/2-x))=0cos(3x-π/4)-cos(π/2-x)=0-2sin(x+π/4)sin(2x-3π/4)=0sin(x+π/4)=0⇒x+π/4=πn⇒x=-π/4+πnsin(2x-3π/4)=0⇒2x-3π/4=πn⇒2x=3π/4+πn⇒x=3π/8+πn/2