решите систему уравнение х+у=5, х^3+у^3=35

x+Y=5⇒y=5-xx³+y³=(x+y)(x²-xy+y²)=355(x²-xy+y²)=35(x²-xy+y²)=35/5=7x²-x(5-x)+(5-x)²-7=0x²-5x+x²+25-10x+x²-7=03x²-15x+18=0x²-5x+6=0x1+x2=5 U x1*x2=6x1=2⇒y1=5-2=3x2=3⇒y2=5-3=2(2;3) U (3;2)