Решите неравенство log_3(x^2-2x)>1

log_3(x`2-2x)>13`1>x`2-2x3>x`2-2xx`2-2x-3>0D=4-4(-3) = 16`D = 4x1 = -1 x2 = 3Ответ: x~(-s;-1)~(3;+s)