Помогите решить [tex] \frac{4}{x^2+6x+9} - \frac{6}{9-x^2} = \frac{1}{x-3} [/tex]

4/(x+3)²+6/(x-3)(x+3)-1/(x-3)=0x≠3 U x≠-34(x-3)+6(x+3)-1*(x+3)²=04x-12+6x+18-x²-6x-9=0x²-4x+3=0x1+x2=4 U x1*x2=3x1=1 x2=3 не удов усл