а) (-1;3) и (2;-2)(x+1)/(-1-2)=(y-3)/(3+2)(x+1)/(-3)=(y-3)/55x+5+3y-9=05x+3y-4=0 б) (4;1) и (-3;-1)(x-4)/(4+3)=(y-1)/(1+1)(x-4)/7=(y-1)/22x-8=7y-72x-8-7y+7=02x-7y-1=0 в) (0;5) и (4;0)(x-0)/(0-4)=(y-5)/(5-0)x/(-4)=(y-5)/55x=-4y+205x+4y-20=0 г) (-3;0) и (0;-6)
(x+3)/(-3-0)=(y-0)/(0+6)(x+3)/(-3)=y/66x+18+3y=0