Помогите решить пример
√2cos(x+п/3)=-1

Решение√2cos(x+π/3) = -1cos(x + π/3) = - 1/√2x + π/3 = (+ -)arccos(-1/√2) + 2πn, n∈zx + π/3 = (+ -)(π - arccos1/√2) + 2πn, n∈zx + π/3 = (+ -)(π - π/4) + 2πn, n∈zx + π/3 = (+ -)(3π/4) + 2πn, n∈zx  = (+ -)(3π/4) - π/3 + 2πn, n∈z