[tex]log_{0,2}(log_{2}(x^2-6x+5)) \geq 0 [/tex]

ОДЗx²-6x+5>0x1+x2=6 u x1*x2=5⇒x1=1 U x2=5x<1 u x>5log(2)(x²-6x+5)>0⇒x²-6x+5>1x²-6x+4>0D=36-16=20x1=(6-2√5)/2=3-√5 u x2=3+√5x<3-√5 U x>3+√5x∈(-∞;3-√5) U (3+√5;∞)log(2)(x²-6x+5)≤1x²-6x+5≤2x²-6x+3≤0D=36-12=24x1=(6-2√6)/2=3-√6 U x2=3+√63-√6≤x≤3+√6x∈[3-√6;3-√5) U (3+√5;3+√6]