√(x + 1) = √ ( 2x + 3)√(x + 1) - √(2x + 3) = 0( x + 1) - ( 2x + 3 ) = 0²x + 1 - 2x - 3 =0- x = - 1 + 3- x = 2x = - 2√ ( x - 2) + 3 = 0√( x - 2) = - 3x - 2 = ( - 3)²x - 2 = 9x = 9 + 2x = 11√(2x - 1) = x - 2(2x - 1) = (x - 2)²2x - 1 = (x - 2)(x - 2)2x - 1 = x² - 2x - 2x + 42x - 1 = x² - 4x + 42x - x² + 4x = 1 + 4- x² + 6x = 5- x² + 6x - 5 = 0x² - 6x + 5 = 0D = b² - 4ac = ( - 6)² - 4 × 1 × 5 = 36 - 20 = 16 = 4²x₁ = 6 + 4 / 2 = 5x₂ = 6 - 4 / 2 = 1√(3 - x) = - 23 - x = ( - 2)²3 - x = 4- x = 4 - 3-x = 1x = - 1√y = - 1y = ( - 1)²y = 1