f(x)=x^2+16/x+4√x-3 f(4)=?

f(x)=x^2+16/x+4√x-3 f(4)=?
- Предмет:
  Алгебра
- Автор:
  koletwsm
- 6 лет назад

Ответы 1

$F(x)=x^2+ \frac{16}{x} +4 \sqrt{x} -3 \\ \\ f(x)=F`(x)=(x^2+ \frac{16}{x} +4 \sqrt{x} -3)`= \\ \\ =2x-\frac{16}{x^2}+4\cdot \frac{1}{2 \sqrt{x} } =2x-\frac{16}{x^2}+\frac{2}{ \sqrt{x} } \\ \\ f(4)=2\cdot 4-\frac{16}{4^2}+\frac{2}{ \sqrt{4} }=8-1+1=8$
- Автор:
  elianpugh
- 6 лет назад
- 0
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f(x)=x^2+16/x+4√x-3 f(4)=?

Ответы 1

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