1/3(6х-3)+2/5(5х-15) при х=3,01 как решить? - №13025687

1/3(6х-3)+2/5(5х-15) при х=3,01 как решить?
- Предмет:
  Алгебра
- Автор:
  madilynuqah
- 6 лет назад

Ответы 1

1/3(6х-3)+2/5(5х-15)=1/3*6х-1/3*3+2/5*5х-2/5*15=2х-1+2х-6=4х-7Если х=3,01,то 4х-7=4*3,01-7= 12,04-7=5,4
- Автор:
  string bean
- 6 лет назад
- 0
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