решить уравнение (2t-3)(5t+2)+(3t-1)(4t+2)=10t²-5

(2t-3)*(5t+2) +(3t-1)*(4t+2)=10t^2-510t^2-15t+4t-6+(12t^2-4t+6t-2)=10t^2-522t^2-9t-8=10t^2-512t^2-9t-8+5=012t^2-9t-3=04t^2-3t-1=0D=9-4*4*(-1)=9+8=17t1=3-√17\8t2=3+√17\8