2sin(7п/2-х)*sinx=cosx помогите решить

2sin(2n+3π/2-x)*sinx=cosx2sin(3π/2+x)sinx=cosx-2cosxsinx=cosxcosx+2cosxsinx=0cosx(1+2sinx)=0cosx=0⇒x=π/2+ππn,n∈Zsinx=-1/2⇒x=(-1)^(k+1)π/6+πk,k∈Z