Решите систему уравнений
3(х+у)+1=х+4у
7-2(х-у)=х-8у

3(х+у)+1=х+4у7-2(х-у)=х-8у3х+3у+1=х+4у7-2х+2у=х-8у2х-у=1-3х+10у=-72х-у=13х-10у=72х-1=у3х-10у=72х-1=у3х-10(2х-1)=72х-1=у3х-20х+10=72х-1=у-17х=-32х-1=ух=3/172·3/17-1=ух=3/176/17-17/17=ух=3/17у=-11/17х=3/17