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РешениеLog₁/₄ (2x-5)>-1ОДЗ: 2x - 5 > 0x > 2,5 ; x ∈(2,5; + ∞)0 < 1/4 < 1, значит2x - 5 < (1/4)⁻¹2x - 5 < 42x < 9x < 4,5x ∈ ( - ∞; 4,5)с учётом ОДЗ получаем: x ∈ (2,5; 4,5)
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Автор:
nibblesmeadows - 5 лет назад
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