Решите,пожалуйста срочно!!
2sinx5x*cos5x-cos5x=0

Решение2sinx5x*cos5x-cos5x=0cos5x(2sin5x - 1) = 01)  cos5x = 05x = π/2 + πk, k∈Zx = π/10 + πk/5, k∈Z2)  sin5x = 1/25x = (-1)^n*arcsin(1/2) + πn, n∈Z5x = (-1)^n*(π/6) + πn, n∈Zx = (-1)^n*(π/30) + π/5, n∈Z