Решите уравнение:
(x-5)^2=1
(3х+6)^2=100
(3-2x)^2=25

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(X-5)^2=1X^2-10x+25=1X^2-10x+24=0D=100-96=4X1=10+2/2=6X2=10-2/2=4(3x+6)^2=1009x^2+36x+36-100=09x^2+36x-64=0D=1296-(-2304)=3600X1=-36+60/18=24/18=8/6=1 1/3X2=-36-60/18=-96/18=-32/6=-5 1/3(3-2x)^2=259-12x+4x^2=254x^2-12x+9-25=04x^2-12x-16=0|:4X^2-3x-4=0D=9+16=25X1=3+5/2=4X2=3-5/2=-1