3*9^х-5*6^х+2*4^х=0 показательное

3·3^2x -5· 2^x·3^x + 2·2^2x = 0 | : 2^2x3·(3/2)2x -5·(3/2)^x + 2 = 0(3/2)^x = t3t² - 5t +2 = 0D = 1t = 1  и  t = 4/6=2/3а) t = 1(3/2)^x = 1x = 0б) (3/2)^x = 2/3x = -1