Решить уравнение .
1) 2^х-1+2^х-2+2^х-3=448
2) 4^х-3×2=40

Извините, не такте задание 4^х-3×2^х=40

1) 2^(x-1) +2^(x-2) +2^(x-3) = 4482^(x-3) (2^2 + 2^1 +1) = 4482^(x-3)·7 = 448 | :72^(x-3) = 642^(x-3) = 2^6x-3 = 6x = 92)4^(x-2) =20(x-2)lg4 = lg20x-2 = lg20/lg4x = lg20/lg4 +2