[tex]2*3^{2x+4} - 245*3^{x}+3 \leq 0[/tex]

Решение2*3^(2x + 4) - 245*(3^x) + 3 ≤ 02*81*(3^2x) - 245*(3^2x) + 3 ≤ 0162*(3^2x) - 245*(3^x) + 3 ≤ 03^x = t162t² - 245t + 3 ≤ 0D = 245² - 4*162*3 =  60025 - 1944 = 58081t₁ = (245 - 241)/324t₁ = 4/324t₁ = 1/81t₂ = (245 + 241)/324t₂ = 486/324t₂ = 1,53^x = 1/813^x = 3⁻⁴x₁ = - 43^x = 3/2log₃ (3^x) = log₃ (3/2)x log₃ 3 = log₃ 3 - log₃ 2x₂ = 1 - log₃ 2x ∈[ - 4; 1 - log₃ 2]илиlog₃ 2 ≈ 0,63x₂ ≈ 1 - 0,63 = 0,37x∈ [- 4 ; 0,37]