Помогите с решением :з

1) (3x+2)^2 = 10+3(x-2)(x+2)
2) (2x-3)^2 = 9-2(x-3)(x+3)
3) (x+2)(x^2-2x+4)-x^2(x+2) = 0
4) (x-1)(x^2+x+1)-x^2(x-1) = 0

1) (3x + 2)(3x + 2) = 10 + 3(x - 2)(x + 2)9x² + 12x + 4 = 10 + 3(x² - 4)9x² + 12x + 4 = 10 + 3x² - 129x² - 3x² + 12x + 4 + 2 = 06x² + 12x + 6 = 0x² + 2x + 1 = 0D = b² - 4ac = 4 - 4 × 1 = 0 - имеет один корень.x = - b/2ax = - 2 / 2 = - 1Ответ: x = - 1.2) (2x - 3)(2x - 3) =9 - 2(x - 3)(x + 3)4x² - 12x + 9  = 9 - 2( x² - 9)4x² - 12x + 9 = 9 - 2x² + 184x² + 2x² - 12x + 9 - 9 - 18 = 06x² - 12x - 18 = 0x² - 2x - 3 = 0D = b² - 4ac = 4 - 4 ×(- 3 )= 4 + 12 = 16 = 4²x1 = (2 + 4)/2 = 3x2 = ( 2 - 4) /2 = - 1.3) (x + 2)(x² - 2x + 4) - x²(x + 2) = 0x³ - 2x² + 4x + 2x² - 4x + 8 - x³ - 2x² = 0- 2x² + 8 = 0- 2x² = - 82x² = 8x² = 4x = 2x = - 24) (x - 1)(x² + x + 1) - x²(x - 1) = 0x³ + x² + x - x² - x - 1 - x³ + x² = 0x² - 1 = 0x² = 1x = 1x = - 1Ответ: x = 1, x = - 1.