Помогите!
4-cos^2*2x=3sin^2*2x+2sin4x

2*(1+сos4x)/2 *3sin4x+4*(1-cos4x)/2=01+cos4x+3sin4x+2-2cos4x=01-cos4x+3sin4x=02sin²2x+6sin2xcos2x=0/2cos²2x≠0tg²2x+3tg2x=0tg2x(tg2x+3)=0tg2x=0⇒2x=πn⇒x=πn/2tg2x=-3⇒2x=-arctg3+πn⇒x=-1/2arctg3+πn/2