1 - cosx - sin x/2 =0

Решение1 - cosx - sin x/2 =01 - (1 - 2sin²x/2) - sinx/2 = 01 - 1 + 2sin²x/2 - sinx/2 = 02sin²x/2 - sinx/2 = 0sinx/2(2sinx/2 - 1) = 0 1)  sinx/2 = 0 x/2 = πk, k∈Zx₁ = 2πk, k∈Z2)   2sinx/2 - 1 = 0sinx/2 = 1/2x/2 = (-1)^narcsin(1/2) + πn, n∈Zx/2 = (-1)^n(π/6) + πn, n∈Zx₂ = (-1)^n(π/3) + πn, n∈ZОтвет: x₁ = 2πk, k∈Z ; x₂ = (-1)^n(π/3) + πn, n∈Z