sin(2x+п/2)=1

cos(x/2-п/3)=0

Решение1)  sin(2x + π/2) = 1cos2x = 12x = 2πk, k∈Zx = πk, k∈Z2)  cos(x/2 - π/3) = 0x/2 - π/3 = π/2 + πn, n∈Zx/2 = π/2 +π/3 +  πn, n∈Zx/2 = 5π/6 +  πn, n∈Zx = 5π/3 +  2πn, n∈Z