log3(3x-1)+log3(1+x)=1+log3(x+3)

log3((3x-1)*(1+x))=log3 3+ log3 (x+3)log3((3x-1)*(1+x)=log3 (3*(x+3))<=><=> (3x-1)*(1+x)=3*(x+3)3x+3x²-1-x=3x+93x²-x-10==0D = 1+120= 121x1= (1+11/6)= 2x2=(1-11/6)= 10/6= 5/3 = 1 целая (2/3)ответ: 1 целая 2/3 2