Уравнения во вложении...

Решение1.  Sin2xcosx+cos2xsinx= √3/2sin(2x + x) = √3/2sin3x = √3/23x = (-1)^x arcsin(√3/2) + πn, n∈ Z3x = (-1)^n *(π/3) + πn, n∈Zx = (-1)^n *(π/9) + πn/3, n∈Z 2.  Cosx+cos²x= 1/2 - sin²x cosx = 1/2 - 1cosx = - 1/2x = (+ -)arccos(-1/2) + 2πn, n ∈ Zx = (+ -)*(π - arccos(1/2)) + 2πn, n ∈ Zx = (+ -)*(π - π/3) + 2πn, n∈Zx = (+ -)*(2π/3) + 2πn, n∈Z3. Sin3xcosx-cos3xsinx = √3/2sin(3x - x) = √3/2sin2x = √3/22x = (-1)^n arcsin(√3/2) + πk, k ∈ Z2x = (-1)^n * (π/3) + πk, k ∈ Zx = (-1)^n * (π/6) + πk/2, k ∈ Z