1. Решите неравенство
а) [tex]( \sqrt[3]{8}) ^{x+6} \ \textgreater \ \frac{1}{9} [/tex]
b) ([tex](1 \frac{2}{7} ) ^{ x^{2} - 4} \leq 1[/tex]

2. Решите систему 
 [tex] \left \{ {{x+y=-2} \atop 6 ^{x+5y} {=36}} ight. [/tex]

1a)2^(x+6)>1/9x+6>log(2)1/9x>-6-log(2)9b)(9/7)^(x²-4)≤1x²-4≤0(x-2)(x+2)≤0x=2 u x=-2x∈[-2;2]2x+y=-2⇒x=-2-y6^(x+5y)=36⇒x+5y=2-2-y+5y=24y=4y=1x=-2-1=-3(-3;1)