f(x) = cos5x · cos(x + π/6)g(x) = sin5x · sin(x + π/6) + 0.5√3cos5x · cos(x + π/6) = sin5x · sin(x + π/6) + 0.5√3 cos5x · cos(x + π/6) - sin5x · sin(x + π/6) = 0.5√3cos (6x + π/6) = 0.5√36x + π/6 = ⁺₋ π/6 + 2πn n∈Z 1) 6x₁ + π/6 = + π/6 + 2πn n∈Z 2) 6x₂ + π/6 = - π/6 + 2πn n∈Z 1) 6x₁ = 2πn n∈Z 2) 6x₂ = - π/3 + 2πn n∈Z1) x₁ = πn/3 n∈Z 2) x₂ = - π/18 + πn/3 n∈ZОтвет: x₁ = πn/3 n∈Z x₂ = - π/18 + πn/3 n∈Z