Cos(x/2-pi/12)(sin(x-pi/3)+1)=0

1) cos(x/2-π/12)=0x/2-π/12=π/2 + πk, k∈Zx/2=π/12  + π/2 + πkx/2= π/12 + 6π/12 + πkx/2 = 7π/12 + πkx= 2(7π/12 + πk)x=7π/6 + 2πk, k∈Z2) sin(x-π/3)+1=0sin(x-π/3)= -1x-π/3= -π/2 + 2πn, n∈Zx=π/3 - π/2 + 2πnx=2π/6 - 3π/6 + 2πnx= - π/6 + 2πn, n∈ZОтвет: 7π/6 + 2πk, k∈Z;            - π/6 + 2πn, n∈Z