12t^2−(4t−3)⋅(3t+1)=−2
^ - то есть степень

12t²-(4t-3)*(3t+1)=-212t²-(12t²+4t-9t-3)=-212t²-(12t²-5t-3)=-212t²-12t²+5t+3=-25t=-2-35t=-5|:5t=-1Ответ:-1

12t^2-12t^2-4t+9t+3=-25t=-5t=-1