Решите уравнение: (4x+3)^2-(3x-1)^2=0

(16x^2+24x+9)-(9x^2-6x+1)=016x^2+24x+9-9x^2+6x-1=07x^2+30x+8=0D=900-224=676=26x1= -30+26/14= -4/14= -2/7x2= -30-26/14 = -56/14= -4