найдите корни уравнения: а) (х-1)(х+2)(х+10)=0
б) 36-x^2=0
в) 5x=-20x
г) 8x-4x^2=0
д) x^2=8
е) (x-2)(x+3)=-6

a) ( x - 1)(x+ 2)(x+ 10) = 0Произведение равно 0,когда один из множителей равен0,значит,x - 1 = 0x = 1x + 2 = 0x = - 2x + 10 = 0x = - 10б) - x² = - 36x² = 36x = 6x = - 6в) 5x = - 20x5x + 20x = 025x = 0x = 0г) - 4x² + 8x = 04x² - 8x = 04x(x - 2) = 04x = 0x = 0x - 2 = 0x = 2д) x² = 8x = √8 = 2√2x = - √8 = - 2√2е) (x - 2)(x + 3) = - 6x² + x - 6 + 6 = 0x² + x = 0x( x + 1) = 0x = 0x + 1 = 0x = - 1